Final answer:
Doubling the diameter of a current loop results in halving the magnetic field strength at the center; therefore, if the original field strength was 2.0 mT, it would become 1.0 mT after doubling the diameter.
Step-by-step explanation:
The question pertains to the magnetic field strength at the center of a current loop. Specifically, it is asking how the magnetic field strength will change if the diameter of the loop is doubled while keeping the current constant. To answer this, we use the formula for the magnetic field at the center of a current loop, B = (\(\mu_{0}\)I)/(2R), where B is the magnetic field strength, \(\mu_{0}\) is the magnetic constant (4\(\pi\) x 10^-7 T\(\cdot\)m/A), I is the current, and R is the radius of the loop.
If the diameter of the loop is doubled, the radius is also doubled. Since the radius R is in the denominator, doubling the radius will halve the magnetic field strength. Therefore, if the magnetic field strength was originally 2.0 mT, when the diameter is doubled, the new magnetic field strength will be 1.0 mT, which is not one of the options provided. None of the options a) 1.4 mT b) 2.8 mT c) 5.6 mT d) 0.7 mT correlate with the calculated outcome.