Final answer:
The critical points of the function f(x) = x³ - 12x - 5 are found by setting the derivative f'(x) to zero, resulting in the points x = 2 and x = -2.
Step-by-step explanation:
The critical points of a function are found by taking the derivative of the function and setting it equal to zero. For the function f(x) = x³ - 12x - 5, we need to calculate f'(x) which gives us 3x² - 12. Setting the derivative equal to zero: 3x² - 12 = 0.
Now we solve for x:
- Divide both sides by 3, we get x² = 4.
- Take the square root of both sides, we get x = ±2.
Therefore, the critical points for the function f(x) = x³ - 12x - 5 are x = 2 and x = -2.