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Determine which point lies on the graph of the equation y=7x²-3x²

A. (0,0)
B. (−2,34)
C. (−1,10)
D. (0,0)
E. (1,4)

1 Answer

5 votes

Final answer:

The points that lie on the graph of the equation y=7x²-3x² are (0,0) and (0,0) (points A and D).

Step-by-step explanation:

The given equation is y = 7x² - 3x². To determine which point lies on the graph of this equation, we need to substitute the x-coordinate and y-coordinate of each point into the equation and check if the equation holds true.

Let's check the points one by one:

  1. Point A: (0,0)
    Substituting x = 0 and y = 0 in the equation, we get 0 = 0. The equation is satisfied, so point A lies on the graph of the equation.
  2. Point B: (-2,34)
    Substituting x = -2 and y = 34 in the equation, we get 34 = 70 - 18. The equation is not satisfied, so point B does not lie on the graph of the equation.
  3. Point C: (-1,10)
    Substituting x = -1 and y = 10 in the equation, we get 10 = 14 + 3. The equation is not satisfied, so point C does not lie on the graph of the equation.
  4. Point D: (0,0)
    Substituting x = 0 and y = 0 in the equation, we get 0 = 0. The equation is satisfied, so point D lies on the graph of the equation.
  5. Point E: (1,4)
    Substituting x = 1 and y = 4 in the equation, we get 4 = 4 - 3. The equation is not satisfied, so point E does not lie on the graph of the equation.

Therefore, the points that lie on the graph of the equation y = 7x² - 3x² are (0,0) and (0,0) (points A and D).

User Cmbarbu
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