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Find the real zero(s) of f(x)=4x^3-16x^2 2.5x

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Final answer:

To find the real zero(s) of the given cubic function, set the function equal to zero and solve for x using the quadratic formula. The real zero of the function is x = 0.

Step-by-step explanation:

To find the real zero(s) of the given function, f(x) = 4x^3 - 16x^2 + 2.5x, we can set the function equal to zero and solve for x.

Rearranging the equation, we have 4x^3 - 16x^2 + 2.5x = 0.

Next, we can use the quadratic formula to solve for the values of x. Using the formula, we find that x ≈ -0.7375, 0, and 1.7375.

However, since we are only looking for real zeros, the only real zero of the function is x = 0.

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