Final answer:
The proportion of the population able to reproduce can be calculated using the dominant allele frequency and the fitness levels of individuals. The values are adjusted for the percentage of heterozygotes and homozygous recessives that are fit to reproduce and added together to obtain the final proportion.
Step-by-step explanation:
To find the proportion of a population able to reproduce based on allele frequencies and fitness levels, we use Hardy-Weinberg principles. Given the dominant allele frequency (p) is 0.7, we can find the recessive allele frequency (q) because p + q = 1. Therefore, q = 0.3. The genotype frequencies in the population can be represented as p² for the homozygous dominant, 2pq for the heterozygotes, and q² for the homozygous recessive individuals.
The proportion of homozygous dominant individuals is then (0.7)², the proportion of heterozygotes is 2*(0.7)*(0.3), and the proportion of homozygous recessive individuals is (0.3)². However, not all of these individuals are fit to reproduce. If 23% of heterozygotes and 44% of homozygous recessive individuals are unfit, then only 77% of heterozygotes and 56% of homozygous recessives are sufficiently fit to reproduce.
The proportion of the population able to reproduce is calculated as follows: the sum of fit homozygous dominant, fit heterozygotes, and fit homozygous recessive individuals. This gives us (0.7)² + (0.77)*(2*(0.7)*(0.3)) + (0.56)*(0.3)². We then calculate the numerical values and sum them to get the final proportion, rounding to two decimal places as required.