Question

if you react 1.1 ml of ethanol with 6 drops of sulfuric acid and 5.345 g of salicylic acid, what is the % yield of the reaction if you synthesized 0.840 g of pure ethyl salicylate? the molecular weight of salicylic acid is 138.12 g/mol, the molecular weight of ethyl salicylate is 166.17 g/mol. the molecular weight of ethanol is 46.069 g/mol and its density is 0.789 g/ml. the molarity of sulfuric acid is 18 mol/l

Answer 1

To find the % yield of the reaction, calculate the theoretical yield of ethyl salicylate and divide it by the actual yield.

Step-by-step explanation:

To find the % yield of the reaction, we need to compare the actual yield (0.840 g of pure ethyl salicylate) to the theoretical yield. First, calculate the number of moles of salicylic acid and ethanol using their molar masses and given amounts. The mole ratio between salicylic acid and ethyl salicylate is 1:1, so the theoretical yield of ethyl salicylate can be calculated. Finally, divide the actual yield by the theoretical yield and multiply by 100 to find the % yield.