Question

A rightward force of 302 N is applied to a 28.6 kg object initially at rest. What is the object's velocity after 6 seconds, assuming no other forces act on it?

a) 34.5 m/s
b) 204.5 m/s
c) 2045 m/s
d) 3.45 m/s

Answer 1

The object's velocity after 6 seconds, calculated using Newton's second law and the formula
`v = at`, is 63.36 m/s. None of the provided multiple-choice options match this result, indicating a possible error in the question.

Step-by-step explanation:

Calculating Velocity

To find the object's velocity after 6 seconds, we start by calculating the acceleration using Newton's second law of motion, which states that force equals mass times acceleration. The acceleration (a) can be expressed as
`a = F/m`. In this scenario, the force (F) is 302 N, and the mass (m) is 28.6 kg. Plugging these values into our equation, we get a = 302 N / 28.6 kg = 10.56 m/s². Since the object starts from rest, we can calculate the velocity (v) after 6 seconds using the formula v = at, where t is the time. Therefore, v = 10.56 m/s² * 6 s = 63.36 m/s. Given the multiple-choice options, none precisely match the calculated velocity, which suggests a possible typo or error in the provided options.