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A centripetal acceleration addict rides in uniform circular motion with period T. What happens to the magnitude of centripetal acceleration if the period is halved?

a) It doubles
b) It halves
c) It quadruples
d) It remains the same

User Hao Wu
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Final answer:

If the period is halved, the magnitude of centripetal acceleration will double.

Step-by-step explanation:

The magnitude of centripetal acceleration is inversely proportional to the period of the circular motion. So, if the period is halved, the magnitude of centripetal acceleration will double. This can be understood by considering the formula for centripetal acceleration: a = 4π2r/T2. As T decreases, the denominator T2 becomes smaller, resulting in a larger value for a.

User LuisEspinoza
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