Question

A circle is defined by the equation {{{{{x}^{2}} {{y}^{2}}} {4x}}-{2y}}={44}x 2 y 2 4x−2y=44, what is the radius of the circle?

Answer 1

To find the radius of the circle defined by the equation x^2 * y^2 - 4x - 2y = 44, rearrange the equation in standard form, complete the square, and compare to the standard form to determine the radius.

Step-by-step explanation:

To find the radius of the circle defined by the equation x^2 * y^2 - 4x - 2y = 44, we need to rewrite the equation in standard form. Start by rearranging the terms to isolate the variables on one side and the constant on the other side of the equation. Then, complete the square by adding the square of half the coefficient of each variable to both sides. Now, the equation should be in the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center of the circle and r is the radius. Finally, comparing the equation to the standard form, we can determine the radius of the circle.