Final answer:
The x-intercepts of the quadratic function f(x) = x² - 12x + 20 are found by setting the function equal to zero and solving for x. By factoring, we find the solutions to be x = 10 and x = 2, corresponding to options b) and c).
Step-by-step explanation:
To find the x-intercepts of the quadratic function f(x) = x² - 12x + 20, we set f(x) to 0 and solve for x. This gives us the equation x² - 12x + 20 = 0. To solve this equation, we can factor it if possible, or use the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a), where a, b, and c are coefficients from the quadratic equation ax² + bx + c = 0.
The x-intercepts of the function f(x)=x²-12x+20 can be found by setting the function equal to zero and solving for x. We can do this by factoring the quadratic equation or by using the quadratic formula. In this case, the factored form of the equation is (x-2)(x-10)=0. Setting each factor equal to zero, we find x=2 and x=10. So the x-intercepts of the function are x=2 and x=10.
In this case, a = 1, b = -12, and c = 20. Factoring the quadratic equation, we get (x - 10)(x - 2) = 0. Therefore, the x-intercepts are x = 10 and x = 2, which corresponds to options b) and c).