Question

Find the linearization Lₛ(x) of the function at a=-2 1. fₛ(x)=− x³+2x²+(1/3)

a) Lₛ(x) = -2x - 1
b) Lₛ(x) = -3x + 4
c) Lₛ(x) = -4x + 3
d) Lₛ(x) = -1x - 2

Answer 1

To find the linearization of the function fₛ(x) = - x³+2x²+(1/3)aat a = -2, we need to find the derivative of the function and evaluate it at a = -2. The linearization is given by the equation: Lₛ(x) = f'(a) * (x - a) + f(a). First, let's find the derivative of fₛ(x).

Step-by-step explanation:

To find the linearization of the function fₛ(x) = - x³+2x²+(1/3)a at a = -2, we need to find the derivative of the function and evaluate it at a = -2. The linearization is given by the equation:

Lₛ(x) = f'(a) * (x - a) + f(a)

First, let's find the derivative of fₛ(x):