160k views
5 votes
0.307 g Al 0.569 g As 0.486 g O

User Johnboiles
by
8.3k points

1 Answer

4 votes

The empirical formula for the same, given that the sample contains 0.307 g Al, 0.569 g As and 0.486 g O is
Al_3As_2O_8

Calculations of empirical formula

We can calculate the empirical formula for the sample by:

  • Dividing each element present in the sample by their molar masses
  • Dividing the result obtained in 1 above by the smallest value

Now, we shall apply the above rule in order to obtain the empirical formula for the sample. This is shown below:

  • Al = 0.307 g
  • As = 0.569 g
  • O = 0.486 g
  • Empirical formula for sample =?

1. Divide each by their molar mass

  • Al = 0.307 / 27 = 0.0114
  • As = 0.569 / 75 = 0.0076
  • O = 0.486 / 16 = 0.0304

2. Divide by the smallest value

  • Al = 0.0114 / 0.0076 = 1.5
  • As = 0.0076 / 0.0076 = 1
  • O = 0.0304 / 0.0076 = 4

3. Since there is a decimal number, multiply each by 2 each to express all in whole number.

  • Al = 1.5 × 2 = 3
  • As = 1 × 2 = 2
  • O = 4 × 2 = 8

Therefore, the empirical formula is
Al_3As_2O_8

Complete question:

A sample contains 0.307 g Al, 0.569 g As and 0.486 g O. What is the empirical formula for the sample?

User Evandrix
by
9.2k points