Final answer:
The question deals with the electrolysis of dilute sodium hydroxide and molten lead bromide, focusing on the electrochemical reactions that occur when electricity passes through these substances.
Step-by-step explanation:
The question is related to the electrolysis of dilute sodium hydroxide (NaOH) and molten lead bromide (PbBr2). When the same quantity of electricity is passed through both, they undergo electrochemical reactions. In the case of dilute sodium hydroxide, water is reduced at the cathode instead of sodium ions due to the lower reduction potential of water. On the other hand, molten lead bromide, when undergoing electrolysis, results in lead metal at the cathode and bromine gas at the anode since the ions are freely movable in the melt.