Final answer:
The expression (⁴)x sin(⁴)x 2si(²)xcos(²)x can be factored as: (⁴)x sin(⁴)x 2si(²)xcos(²)x = (sin²x)²(2sin²x cos²x).
Step-by-step explanation:
The expression (⁴)x sin(⁴)x 2si(²)xcos(²)x can be factored as:
(⁴)x sin(⁴)x 2si(²)xcos(²)x = (sin²x)²(2sin²x cos²x)
So, the correct answer is b) sin²x cos²x.