Final answer:
To solve the system of linear equations 3x - 2y = -5 and 4x + 5y = 47, we can use the substitution method or the elimination method. By using the substitution method, we find that x = 3 and y = 7.
Step-by-step explanation:
To solve the system of linear equations 3x - 2y = -5 and 4x + 5y = 47, we can use either the substitution method or the elimination method. Let's use the substitution method:
1. Solve the first equation for x:
3x - 2y = -5 --> 3x = 2y - 5 --> x = (2y - 5) / 3
2. Substitute the value of x into the second equation:
4((2y - 5) / 3) + 5y = 47
3. Simplify and solve for y:
(8y - 20) / 3 + 5y = 47 --> 8y - 20 + 15y = 141 --> 23y = 161 --> y = 7
4. Substitute the value of y back into the first equation to solve for x:
3x - 2(7) = -5 --> 3x - 14 = -5 --> 3x = 9 --> x = 3
Therefore, the solution to the system of linear equations is x = 3 and y = 7.