Final answer:
There are four different isomers of the aromatic compound with the formula C6H3Br3: 1,3,5-tribromobenzene; 1,2,4-tribromobenzene; 1,2,3-tribromobenzene; and 1,3,4-tribromobenzene.
Step-by-step explanation:
The question is asking how many different aromatic compounds have the formula C6H3Br3, and requires that these isomers be drawn and named. For a six-membered aromatic ring such as benzene, with three substituents, there are several possible arrangements for the bromine atoms. These arrangements are called isomers and each one is unique because the bromine atoms can be placed in different positions around the ring.
To find the number of isomers, consider the following positions for the first bromine atom: it can be placed in any carbon of the ring without restriction. The second bromine has now five remaining positions, but after excluding the position adjacent to the first bromine to avoid the creation of 1,2-dibromobenzene (which doesn't contribute to the C6H3Br3 formula), only four positions remain. The third bromine then has three positions if it is to avoid adjacent placement next to the other bromines. This results in the possible isomer combinations of 1,3,5-tribromobenzene; 1,2,4-tribromobenzene; 1,2,3-tribromobenzene; and 1,3,4-tribromobenzene.
Therefore, there are four different isomers of the aromatic compound with the formula C6H3Br3.