Final answer:
If nondisjunction occurs during meiosis I in a cell with 5 homologous pairs of chromosomes, two gametes would have 6 chromosomes (n + 1) and two would have 4 chromosomes (n - 1).
Step-by-step explanation:
If a parent cell has 5 homologous pairs of chromosomes and a nondisjunction event occurs during meiosis I involving one chromosome, this would lead to an abnormal distribution of chromosomes in the resulting gametes.
Specifically, nondisjunction in meiosis I means that the homologous chromosomes fail to separate properly.
As a result, two of the gametes would have an extra chromosome (n + 1), and two gametes would be missing a chromosome (n - 1).
Since the original cell had 5 pairs (10 chromosomes), the normal haploid number (n) should be 5.
Therefore, in this scenario, two of the gametes would end up with 6 chromosomes, and the other two would have only 4 chromosomes.