Question

A proton is accelerated through an electric field. What was the potential difference that stopped the proton?

A) 1 V
B) 0.5 V
C) 2 V
D) 3 V

Answer 1

The question seeks to determine the potential difference that stopped a proton accelerated through an electric field but lacks specifics on the kinetic energy gained or the work done on the proton for an exact calculation.The answer would require additional information or context about the kinetic energy .

Step-by-step explanation:

The question relates to the concept of electric potential difference and the energy gained by a charged particle when it is accelerated through an electric field. The scenario described pertains to a proton, which, like electrons, will also gain kinetic energy equal to the work done on it by the electric field when it is accelerated. For a charged particle, such as a proton with a charge q, gaining kinetic energy KE from rest, the potential difference V it has been accelerated through is given by the equation V = KE/q. Here, KE is the kinetic energy acquired by the proton, q is the charge of a proton, which is 1.6 × 10-19 C, and V is the potential difference.

Without the specific values for the kinetic energy acquired by the proton, we cannot calculate the exact potential difference. The answer would require additional information or context about the kinetic energy or the work done on the proton to provide a precise answer, thus we cannot determine which option (A, B, C, or D) is the correct option.