Final answer:
The mass of Mg in 1.801.80 g of MgCO3 is calculated using the molar mass of MgCO3 and the given mass to determine the fraction of Mg, resulting in a mass of 0.520.52 g of Mg.
Step-by-step explanation:
To find the mass of Mg in 1.801.80 g of MgCO3, first calculate the molar mass of MgCO3 as the sum of the atomic masses of Mg (24.305 g/mol), C (12.01 g/mol), and three O atoms (3 × 16.00 g/mol), which is 24.305 + 12.01 + 48.00 = 84.315 g/mol. Next, determine the fraction of Mg in MgCO3 by dividing the atomic mass of Mg by the molar mass of MgCO3, which is 24.305/84.315. Finally, multiply this fraction by the given mass of MgCO3 to find the mass of Mg: (24.305/84.315) × 1.801.80 g = 0.520.52 g.