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Rigel IV is 10.8 light-years from Earth:
A) true
B) false

User Shehaaz
by
8.1k points

1 Answer

2 votes

Final answer:

Star A appears 4 times brighter than Star B.

Step-by-step explanation:

Star A and Star B have different apparent brightnesses but identical luminosities. If Star A is 20 light-years away from Earth and Star B is 40 light-years away from Earth, we can determine which star appears brighter by comparing their distances. The apparent brightness of a star decreases as its distance from Earth increases. Since Star A is closer to Earth than Star B, it will appear brighter.

The apparent brightness of a star decreases with the square of the distance. If Star A is 20 light-years away and appears brighter than Star B, which is 40 light-years away, by a factor of x, then the brightness ratio can be calculated using the equation:

x = (distance of Star A / distance of Star B)^2

Plugging in the given values, we have:

x = (20 / 40)^2 = (1/2)^2 = 1/4

Therefore, Star A appears 4 times brighter than Star B.

User Smurff
by
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