Question

When the equation

?PbS+? O₂ →? PbO+? SO2
is balanced, he coefficients are
1. 2; 6; 4; 4
X 2. 1; 2; 1; 1
3. 4; 12; 4; 4
4. 2; 3; 2; 2
5. 2; 2; 1; 2

Answer 1

The balanced chemical equation for the reaction of lead(II) sulfide with oxygen, which produces lead(II) oxide and sulfur dioxide, has the coefficients 2, 3, 2, and 2.The balanced equation is: 2PbS + 3O₂ → 2PbO + 2SO₂ This corresponds to option 4 provided by the student.

Step-by-step explanation:

The question is about balancing a chemical equation. Balancing chemical equations involves adding coefficients in front of chemical formulas to ensure that the number of atoms for each element is the same on both the reactant and product sides of the equation.

Using the principle of conservation of mass, the balanced equation for the reaction of lead(II) sulfide (PbS) with oxygen (O₂) to form lead(II) oxide (PbO) and sulfur dioxide (SO₂) is:

PbS + O₂ → PbO + SO₂

When balancing, it is clear that the coefficients that balance the equation are 2, 3, 2, and 2, respectively. That corresponds to option 4 in the student's list of options.

Now, the balanced equation is: 2PbS + 3O₂ → 2PbO + 2SO₂