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mass 2.50 kg and radius 20.0 cm. a very light wire is wrapped around the rim of the pulley, and a steady downward force of 15.0 n is applied to the wire. what is the magnitude of the angular acceleration of the pulley?

User Athina
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1 Answer

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Final answer:

The magnitude of the angular acceleration of the pulley can be calculated using the equation τ = Iα, where τ is the torque applied to the pulley, I is the moment of inertia of the pulley, and α is the angular acceleration. In this case, the steady downward force applied to the wire is equivalent to the torque applied to the pulley. Therefore, using the given values, we can calculate the magnitude of the angular acceleration as 0.5 rad/s².

Step-by-step explanation:

The magnitude of the angular acceleration of the pulley can be calculated using the equation:

τ = Iα

Where τ is the torque applied to the pulley, I is the moment of inertia of the pulley, and α is the angular acceleration.

In this case, the steady downward force applied to the wire is equivalent to the torque applied to the pulley.

Therefore, we can use the equation:

τ = F × r

Where F is the force and r is the radius of the pulley. Plugging in the values, we get:

τ = 15 N × 0.2 m = 3 N·m

Now, we can rearrange the first equation to solve for α:

α = τ / I

Plugging in the values, we get:

α = 3 N·m / 6 kg·m² = 0.5 rad/s²

Therefore, the magnitude of the angular acceleration of the pulley is 0.5 rad/s².

User Nicholas Hazel
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