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What is the magnitude of the electric flux through the rectangle if E⃗ = (100ı^ − 210ȷ^) N/C?

a) 310 Nm²/C
b) 400 Nm²/C
c) 500 Nm²/C
d) 600 Nm²/C

User Jiten
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1 Answer

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Final answer:

The magnitude of the electric flux through the rectangle is 310 Nm²/C.

Step-by-step explanation:

The electric flux (Φ) through a surface is given by the formula: Φ = E.A, where E is the electric field and A is the area of the surface. In this case, the rectangle is perpendicular to the electric field, so the direction of the electric field is parallel to the area vector. The magnitude of the electric flux is equal to the dot product of the electric field and the area:

Φ = E.A = |E|.|A| = (100 N/C) − (210 N/C) = 310 Nm²/C

User Roland Pihlakas
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