Question

An insulated cup contains 75g of water at 24 degrees. A 26g sample of metal at 82.25 degrees is added. The final temperature of the water and metal is 28.34 degrees. What is the specific heat of the metal?

a. 1.9J/g'C
b. 0.7J/g'C
c. 2.5J/g'C
d. 3.8J/g'C

Answer 1

To find the specific heat of the metal, use the formula Q(metal) + Q(water) = 0 and calculate Q(metal) using the formula Q(metal) = m(metal) * c(metal) * ΔT.

Step-by-step explanation:

To find the specific heat of the metal, we can use the formula:

Q(metal) + Q(water) = 0

Where Q(metal) is the heat gained or lost by the metal and Q(water) is the heat gained or lost by the water. We can calculate Q(metal) using the formula:

Q(metal) = m(metal) * c(metal) * ΔT

Where m(metal) is the mass of the metal, c(metal) is the specific heat of the metal, and ΔT is the change in temperature. Using the given values, we can plug them into the formula and solve for c(metal). The answer is option a. 1.9J/g'C.