Final answer:
The question cannot be directly answered without additional information about the bicarbonate reaction. Instead, by using the ideal gas law and the molar mass of CO2, it's calculated that approximately 0.0788 grams of CO2 would be produced from 40 mL of CO2 at standard temperature and pressure.
Step-by-step explanation:
The student asked how many grams of bicarbonate would produce 40 ml of CO2 gas. To answer this, we adhere to the ideal gas law and look for the molar mass of CO2 (44.01 g/mol). However, the question cannot be answered directly from the options given without the reaction of bicarbonate that produces the CO2. Instead, let's focus on the CO2. At standard temperature and pressure (STP), one mole of any gas occupies 22.4 L. Thus, to find the number of moles in 40 mL of CO2, we use this relation and then multiply by the molar mass of CO2 to find the grams of CO2 produced.
To start the calculation:
- Convert 40 mL to liters (40 mL × 0.001 L/mL = 0.04 L).
- Calculate moles of CO2 using the volume at STP (0.04 L / 22.4 L/mol = 0.00179 mol).
- Multiply moles by molar mass (0.00179 mol × 44.01 g/mol ≈ 0.0788 grams of CO2).
Since the question does not provide enough information about the reaction itself, we cannot directly determine how many grams of bicarbonate are needed. We only calculated the grams of CO2 that would be produced.