Final answer:
Bromochlorofluoromethane (CHBrClF) follows the AX4 classification in the AXmEn system since it has four bonding pairs of electrons with no lone pairs, resulting in a tetrahedral geometric shape.
Step-by-step explanation:
The AXmEn notation is used to describe the shape of a molecule, where 'A' is the central atom, 'X' is a bonding pair of electrons with an atom attached, 'm' is the number of X groups, 'E' is a non-bonding pair of electrons, and 'n' is the number of E pairs. For bromochlorofluoromethane (CHBrClF), which is a halogenated hydrocarbon, the central carbon atom is bonded to one bromine, one chlorine, and one fluorine atom, with the remaining bond to a hydrogen atom. Since all four bonds are to different atoms, we don't need to number them as there's only one carbon atom.
Thus, in bromochlorofluoromethane, the carbon atom (C) is surrounded by three halogen atoms (Br, Cl, F) and one hydrogen (H) with no non-bonding pairs of electrons. This would give bromochlorofluoromethane an AX4 classification, indicating a tetrahedral geometry similar to methane with no non-bonding electron pairs. We can predict the shape of the molecule to be tetrahedral, with bond angles close to 109.5 degrees, just like methane.