Question

I have 470 milligrams of table salt, which is the chemical compound NaCl. How many liters of NaCl solution can I make if I want the solution to be 0.90% NaCl? (9 grams of salt per 1000 grams of solution ).

Answer 1

Using 0.47 grams of NaCl (converted from 470 milligrams), you can prepare approximately 0.0522 liters of a 0.90% NaCl solution by using the mass percentage concentration and assuming the density is similar to that of water.

Step-by-step explanation:

The student has asked how many liters of a 0.90% NaCl solution can be made with 470 milligrams of table salt. We first need to convert the mass of NaCl in grams since the percentage solution is based on grams.

470 milligrams is equal to 0.47 grams. A 0.90% NaCl solution means that there are 9 grams of NaCl per 1000 grams (or 1 liter) of solution. So we need to determine how many liters would contain 0.47 grams of NaCl at this concentration.

First, set up a proportion based on the definition of a percentage:

1. 9 grams NaCl is to 1000 grams of solution as 0.47 grams NaCl is to x grams of solution.
2. To find x, we cross multiply and divide: (0.47 grams * 1000 grams) / 9 grams.
3. The result from step 2 gives us the total grams of solution needed.
4. Since the density of the solution is close to water (1 g/mL), we can approximately equate grams of solution to milliliters of solution, thus converting it to liters.

The calculation is (0.47 * 1000) / 9 = 52.22 grams, which is approximately 52.22 mL since the density of this solution can be assumed to be close to that of water. In liters, this is 0.0522 liters.

Therefore, with 470 mg (0.47 g) of NaCl, we can prepare approximately 0.0522 liters of a 0.90% NaCl solution.