Question

a steam catapult launches a jet aircraft from the aircraft carrier John C. Stennis, giving it a speed of 140 mi/h in 2.20 s. Find the average acceleration of the plane. Assuming the acceleration is constant, find the distance the plane moves.

Answer 1

The average acceleration of the plane is 63.6 mi/h/s. The distance the plane moves is 154.7 mi.

Step-by-step explanation:

To find the average acceleration of the plane, we can use the equation:

acceleration = (final velocity - initial velocity) / time

In this case, the final velocity is 140 mi/h, the initial velocity is 0 mi/h (since the plane starts from rest), and the time is 2.20 s. Plugging these values into the equation gives:

acceleration = (140 mi/h - 0 mi/h) / 2.20 s = 63.6 mi/h/s

To find the distance the plane moves, we can use the equation:

distance = initial velocity * time + (1/2) * acceleration * time^2

In this case, the initial velocity is 0 mi/h, the acceleration is 63.6 mi/h/s, and the time is 2.20 s. Plugging these values into the equation gives:

distance = 0 mi/h * 2.20 s + (1/2) * 63.6 mi/h/s * (2.20 s)^2 = 154.7 mi