Question

A satellite orbiting the moon very near the surface has a period of 110 min. Use this information, together with the radius of the moon r=1.74×106m, to calculate the free-fall acceleration on the moon's surface. What is the moon's acceleration due to gravity? a. 1.60 m/s²

b. 1.75 m/s²
c. 1.43 m/s²
d. 1.23 m/s²

Answer 1

To calculate the acceleration due to gravity on the moon's surface, you can use the formula g = (4π²r) / T². Plugging in the given values, the acceleration due to gravity on the moon is approximately 1.60 m/s².

Step-by-step explanation:

To calculate the acceleration due to gravity on the moon's surface, we can use the equation:

g = (4π²r) / T²

Where r is the radius of the moon and T is the period of the satellite's orbit. Plugging in the given values, we have:

g = (4π² * (1.74 × 10^6)) / (110 * 60)^2

Simplifying the equation gives us:

g ≈ 1.60 m/s²

Therefore, the correct answer is (a) 1.60 m/s².