185k views
1 vote
Identify the zeros of each quadratic equation below.

A. x² - 4 = 0
B. 2x² + 3x + 1 = 0
C. 4x² - 9 = 0
D. x² + 5x + 6 = 0

1 Answer

7 votes

Final answer:

The zeros of each quadratic equation are found using the quadratic formula or by factoring, leading to the zeros: A. ±2, B. two real solutions, C. ±3/2, and D. -2, -3.

Step-by-step explanation:

The zeros of a quadratic equation ax²+bx+c = 0 can be found using the quadratic formula, which is x = (-b ± √(b²-4ac))/(2a). For the given equations:

  1. For A. x² - 4 = 0, the zeros are x = ±2 because x² = 4.
  2. For B. 2x² + 3x + 1 = 0, we apply the quadratic formula to find the zeros: x = (-3 ± √(3²-4*2*1))/(2*2), which simplifies to two real solutions.
  3. For C. 4x² - 9 = 0, this is a difference of squares which can be written as (2x + 3)(2x - 3) = 0, giving zeros at x = ±3/2.
  4. For D. x² + 5x + 6 = 0, this can be factored to (x + 2)(x + 3) = 0, yielding zeros at x = -2 and x = -3.

For the additional equation x² + 1.2 x 10⁻²x - 6.0 × 10⁻³ = 0, using the quadratic formula will provide its zeros. The same method applies for x² +0.0211x -0.0211 = 0, rearranging it into standard quadratic form and then applying the quadratic formula.

User Phydeaux
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories