Final answer:
The magnitude of the horizontal force required to hold the block in equilibrium on the incline is 19.6 N, and the magnitude of the normal force on the block is 9.8 N.
Step-by-step explanation:
To determine the magnitude of the horizontal force required to hold a 2 kg block in equilibrium on a 60° incline, we can use trigonometry. The force can be divided into two components: the normal force perpendicular to the incline and the force parallel to the incline. The magnitude of the force parallel to the incline can be found using the formula: force = mass * acceleration, where acceleration is determined by the angle of the incline. The magnitude of the normal force can be found using the formula: normal force = mass * gravitational force * cos(incline angle).
So, in this case, the magnitude of the horizontal force is 2 kg * 9.8 m/s² * sin(60°) = 19.6 N. The magnitude of the normal force is 2 kg * 9.8 m/s² * cos(60°) = 19.6 N * 0.5 = 9.8 N.