Question

a rocket moves upward, startin from rest with an an accelleration of 29.4 m/s for . It runs out of fuel at the end of 5.65s but does not stop. How high does it rise above the ground?

Answer 1

The rocket rises approximately 46.12 meters above the ground.

Step-by-step explanation:

To determine the height the rocket reaches, we can use the equation: h = (1/2) * a * t^2

Given that the rocket starts from rest and accelerates at a rate of 29.4 m/s² for 5.65 seconds, we can substitute these values into the equation:

h = (1/2) * 29.4 m/s² * (5.65 s)^2

Simplifying the equation, we get:

h = 1/2 * 29.4 m/s² * 31.9225 s^2

h ≈ 46.1185 m

Therefore, the rocket rises approximately 46.12 meters above the ground.