Final answer:
The ball hits the ground approximately 75 meters from the base of the cliff.
Step-by-step explanation:
To solve this problem, we can use the equations of motion for projectile motion. Since the ball is thrown horizontally, the initial vertical velocity is 0 m/s. We can use the equation d = (1/2)gt^2 to find the time it takes for the ball to fall from the cliff to the ground. Plugging in the values, we have 45 = (1/2)(9.8)t^2. Solving for t gives us t ≈ 3 seconds. Since the ball is thrown horizontally at a speed of 25 m/s, the distance it travels horizontally can be found using the equation d = vt. Plugging in the values, we have d = (25 m/s)(3 s) = 75 m. Therefore, the ball hits the ground approximately 75 meters from the base of the cliff. The correct answer is a. 75m.