Final answer:
The jogger and the car both have an acceleration of 1.5 m/s². The car travels further than the jogger during the 2.0-second time interval. The jogger covers a distance of 3.0 meters, while the car covers a distance of 77.0 meters.
Step-by-step explanation:
The acceleration of the jogger can be calculated using the equation:
acceleration = (final velocity - initial velocity) / time
Plugging in the given values, we get:
acceleration = (3.0 m/s - 0) / 2.0 s = 1.5 m/s²
The acceleration of the car can be calculated in the same way:
acceleration = (41.0 m/s - 38.0 m/s) / 2.0 s = 1.5 m/s²
Since both the jogger and the car have the same acceleration, they both cover the same distance during the 2.0-second time interval. The distance covered by an object under constant acceleration can be calculated using the equation:
distance = initial velocity * time + (0.5 * acceleration * time²)
Plugging in the given values for the jogger:
distance = 0 * 2.0 s + (0.5 * 1.5 m/s² * (2.0 s)²) = 3.0 meters
Plugging in the given values for the car:
distance = 38.0 m/s * 2.0 s + (0.5 * 1.5 m/s² * (2.0 s)²) = 77.0 meters