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A car accelerates from rest to a speed of 40 mi/h in 12s Find

(a) The distance the car travels during this time and
(b) The constant acceleration of the car.

User Murugesh
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1 Answer

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Final answer:

The car travels a distance of 480 miles during the 12-second acceleration. The car's constant acceleration is 3.33 mi/h/s.

Step-by-step explanation:

To find the distance the car travels, we can use the formula:

d = (vf - vi)t

where d is the distance, vf is the final velocity, vi is the initial velocity (which is 0 in this case), and t is the time.

Plugging in the given values, we have:

d = (40 mi/h)(12 s) = 480 miles

So, the car travels a distance of 480 miles.

To find the constant acceleration of the car, we can rearrange the formula:

vf = vi + at

solving for a, we have:

a = (vf - vi)/t

Plugging in the given values, we have:

a = (40 mi/h - 0)/12 s = 3.33 mi/h/s

So, the car's constant acceleration is 3.33 mi/h/s.

User Fatima
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