Question

Y=x^2 2x-1 y=3x 5 solve algebraically

(y = 3x + 5\)
A. One point
B. Two points
C. No points
D. Infinite points

Answer 1

To solve the equation y = 3x + 5 algebraically, we can find the y-intercept as (0, 5) and then find another point by substituting a value of x into the equation. By doing so, we determine that the equation has two points that satisfy it.

Step-by-step explanation:

To solve the equation y = 3x + 5 algebraically, we need to find the points where the equation intersects the x-axis. Since the equation is in slope-intercept form y = mx + b, where m is the slope and b is the y-intercept, we can directly identify the y-intercept as (0, 5). To find another point, we can substitute any value of x into the equation and solve for y. Let's substitute x = 1:

y = 3(1) + 5 = 3 + 5 = 8

So, we have another point (1, 8). Therefore, the equation y = 3x + 5 has two points that satisfy it.