Final answer:
To calculate the evaporation of water, we consider the energy requirement of 2,250 J/g and the rate of energy transfer. Evaporating 3 g/min of water seems reasonable in conditions of low humidity, equating to 180 g/hour. Problem-solving strategies involving heat transfer and phase change concepts are applied for accurate calculations.
Step-by-step explanation:
Calculating Water Evaporation,
To calculate the grams of water that would evaporate, we must consider various factors, such as the amount of energy required for evaporation and the rate at which energy is transferred. Starting with the given scenario where it requires 2,250 J to evaporate each gram of water, we can calculate the additional time needed to boil off all the water if we know the energy input rate. For perspiration rates, evaporating about 3 g/min is reasonable on a hot dry day, translating to roughly 180 g/hour. This is under the assumption that the relative humidity is low, which facilitates quicker evaporation.
In the scenario where 1.00 kW/m² of solar energy is balanced by evaporation from a lake, we need to calculate the mass of water that would evaporate in one hour from each square meter. Using the provided data, we can apply the Problem-Solving Strategies for the Effects of Heat Transfer to find the answer. Similarly, we can use the specific heat of vaporization of water to calculate the grams of coffee needed to evaporate to cool it from 95°C to 45°C.
Overall, the evaporation rate, energy requirements, and specific heat properties of water are crucial for solving problems related to heat transfer and phase changes.