Final answer:
The zeros of the function f(x) = 2x^2 - 2x - 12 are x = -2 and x = 3.
Step-by-step explanation:
The zeros of the function f(x) = 2x^2 - 2x - 12 can be found by setting the function equal to zero and solving for x using the quadratic formula.
To use the quadratic formula, we need to rearrange the equation to the form ax^2 + bx + c = 0. In this case, the equation becomes 2x^2 - 2x - 12 = 0.
Using the quadratic formula, we can determine the solutions: x = (-b ± √(b^2 - 4ac))/(2a). Substituting the values of a = 2, b = -2, and c = -12, we get x = (-(-2) ± √((-2)^2 - 4(2)(-12)))/(2(2)). Solving this equation gives us two possible values for x: x = -2 and x = 3.