Final answer:
The strength of the electric field generated by two parallel charged plates is inversely proportional to the distance between them; if the distance is doubled, the field strength is halved.
Step-by-step explanation:
The relationship between electric field density, plates, and distance involves understanding how electric fields are created by charge distributions and how their strength varies with distance.
When considering two parallel conducting plates with a fixed potential difference, charges distribute uniformly across the plates, creating an electric field between them. This field is represented as E in the equation E = V/d, where V is the potential difference and d is the distance between the plates.
As d increases, the field strength decreases, meaning that the electric field is inversely proportional to the distance.
If the potential difference is held constant and the distance between the plates is increased, the isolines of the electric potential will spread farther apart, indicating a reduction in electric field strength.
Moreover, the relationship among units tells us that 1 newton per coulomb (N/C) equals 1 volt per meter (V/m). Therefore, if the distance between the plates is doubled, the electric field strength is halved.