116k views
2 votes
Solve the equation \(\log_3(x-4) + 4 = 6\).

A. \(x = 10\)
B. \(x = 11\)
C. \(x = 12\)
D. \(x = 13\)

User Diehell
by
8.4k points

1 Answer

6 votes

Final answer:

To solve the logarithmic equation, isolate the logarithm, convert it to an exponential form, simplify, and solve for the variable, which results in x = 13.

Step-by-step explanation:

To solve the equation \(log_3(x-4) + 4 = 6\), we first need to isolate the logarithm on one side. This is done by subtracting 4 from both sides of the equation, getting \(log_3(x-4) = 2\).

Next, we apply the property of logarithms that states if \(log_b(a) = c\), then \(b^c = a\). This means we need to express the equation in exponential form: \(3^2 = x - 4\).

Then, simplify the exponential expression: \(9 = x - 4\). Now, we add 4 to both sides to find the value of x: \(x = 13\).

Therefore, the correct answer is D. \(x = 13\).

User Ankur Khandelwal
by
7.8k points