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Factor the expression 81a⁴−256 completely.

A) (9a² + 16)(9a² - 16)
B) (3a² + 4)(27a² - 64)
C) (9a² + 16)(9a² + 16)
D) (3a² - 4)(27a² + 64)

1 Answer

1 vote

Final answer:

The expression 81a⁴−256 can be factored as a difference of squares, resulting in the factored form (9a² + 16)(9a² − 16), making option A correct.

Step-by-step explanation:

To factor the expression 81a⁴−256 completely, we recognize that both 81 and 256 are perfect squares, and a⁴ is also a perfect square (being (a²)²). The expression can be rewritten as (9a²)² − 16², which is a difference of squares. A difference of squares can be factored as (A+B)(A−B), where A and B are the square roots of the first and second terms respectively.

Hence, (9a²)² − 16² = (9a² + 16)(9a² − 16), which is the product of a binomial and its conjugate. Thus, option A) (9a² + 16)(9a² − 16) is the correct option in the final answer.

To factor the expression 81a⁴−256 completely, we can use the difference of squares formula, which states that a² - b² can be factored as (a + b)(a - b). In this case, we have 81a⁴ = (9a²)² and 256 = 16².

So, the expression can be written as (9a² + 16)(9a² - 16). Therefore, the correct option is A) (9a² + 16)(9a² - 16).

User James Henstridge
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