Final answer:
The stone's total air time is 0.319 seconds, its maximum height is 0.169 meters, its range is 15.2 meters, and its final velocity is 15.2 m/s horizontally.
Step-by-step explanation:
Given the initial speed of the stone as 15.2 m/s and the height of the slingshot as 1.1 m, we can use the equations of projectile motion to determine various parameters of the stone's motion.
a) Total air time:
The time for projectile motion is completely determined by the vertical motion. The stone has an initial vertical velocity of 0 m/s (since it is horizontally launched), and it lands 1.1 m below its starting altitude. Using the formula for vertical displacement, we can determine that the stone will spend 0.319 seconds in the air.
b) Maximum height:
Since the stone is launched horizontally, it has no vertical initial velocity. The vertical motion of the stone can be determined using the formula for vertical displacement. The stone will reach a maximum height of 0.169 meters above its starting altitude.
c) Range:
The horizontal motion of the stone can be determined by using the formula for horizontal displacement. The range of the stone is 15.2 meters.
d) Final velocity:
Since the stone is launched horizontally, its final vertical velocity is the same as its initial vertical velocity, which is 0 m/s. Therefore, the final velocity of the stone is 15.2 m/s horizontally.