Final answer:
The 2nd term in the expansion of (2x³)⁵ is 10240x^8.
Step-by-step explanation:
To find the 2nd term in the expansion of (2x³)⁵, we can use the formula for the k-th term of a binomial expansion: T(k) = nC(k-1) * a^(n-k+1) * b^(k-1), where n is the power of the binomial, k is the term number, a is the coefficient, and b is the variable. In this case, n = 5, k = 2, a = 2^5 = 32, and b = (x³)^(5-2) = x^9. Plugging these values into the formula, we get: T(2) = 5C(2-1) * 32^(5-2+1) * x^(9-1) = 5 * 32^4 * x^8 = 320 * 32 * x^8 = 10240x^8. Therefore, the 2nd term in the expansion is 10240x^8. Option B) 320x⁶ is incorrect.