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Y' = 2y/3x, (8, 2) find an equation.

A) y = 2e^(2/3x)
B) y = 2e^(2/3)
C) y = e^(2/3x)
D) y = e^(2/3)

1 Answer

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Final answer:

After separating and integrating the given differential equation y' = 2y/3x and applying the initial condition (8, 2), none of the provided options are correct. The specific solution is y = (2/e^(16/3))e^(2/3x), which does not match any of the answer choices.

Step-by-step explanation:

The given differential equation is y' = 2y/3x. We are looking for a solution that passes through the point (8, 2). This equation is separable, so we can write it as dy/y = (2/3)dx/x and then integrate both sides. The general solution of this equation is y = Ce^(2/3x), where C is a constant that we can find using the initial condition given by the point (8,2).

To find the constant C, we plug in x = 8 and y = 2 into the general solution:
2 = Ce^(2/3(8))
C = 2/e^(16/3)

The specific solution that goes through the point (8, 2) is y = (2/e^(16/3))e^(2/3x).

Comparing with the provided options, none of them match exactly with the standard form of the specific solution we found. The closest option is A) y = 2e^(2/3x), which would be correct if x = 0 and y = 2; however, given the initial condition (8, 2), this option does not satisfy it when plugged into the equation. Therefore, all options are incorrect under the given initial condition.

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