Question

Sketch the parabola of equation y=x²−6x 9, and indicate its vertex.

A) Vertex at (3, 0)
B) Vertex at (2, -1)
C) Vertex at (3, 9)
D) Vertex at (0, -9)

Answer 1

To sketch the parabola of equation y=x²−6x+9 and indicate its vertex, first find the x-coordinate of the vertex using the formula x = -b/2a. Then, substitute the x-coordinate into the equation to find the y-coordinate. The vertex of the parabola is (3, 0).

Step-by-step explanation:

To sketch the parabola of equation y=x²−6x+9 and indicate its vertex, we can start by finding the x-coordinate of the vertex using the formula x = -b/2a. In this equation, a = 1, and b = -6. Plug these values into the formula to get x = -(-6)/(2*1) = 3. So, the x-coordinate of the vertex is 3.

To find the y-coordinate of the vertex, substitute the value of x into the original equation: y = (3)² - 6(3) + 9 = 0. Therefore, the vertex of the parabola is (3, 0).

So, the correct answer is A) Vertex at (3, 0).