Question

Given the variables s, t, and h where s=16t² and s h=64, find δh for the interval t=1 to t=1.1.

A) 1.6
B) 1.2
C) 2.4
D) 2.0

Answer 1

To find δh for the interval t=1 to t=1.1, we can calculate the values of h at t=1 and t=1.1 using the given equation s=16t² and s=64. Then, subtract the value of h at t=1 from the value of h at t=1.1 to find δh.

Step-by-step explanation:

To find δh for the interval t=1 to t=1.1, we need to find the values of h at both t=1 and t=1.1. Given the equation s=16t² and s=64, we can solve for t and h.

At t=1, we have s=16(1)²=16 and at t=1.1, we have s=16(1.1)²=19.36. So, δh = h(t=1.1) - h(t=1) = 19.36 - 16 = 3.36