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An unknown substance enters Earth's atmosphere from outer space. The object displaces 112.4 mL of water and weighs 8.3 oz. What is its density?

a 0.07 g/mL
b 2.1 g/mL
c. 10.2 g/mL
d. 16.2 g/mL
e. 13.5 g/mL

1 Answer

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Final answer:

The density of the unknown substance is 2.091 g/mL.

Step-by-step explanation:

To calculate the density of the unknown substance, we can use the formula: density = mass/volume. In this case, the mass of the unknown substance is given as 8.3 oz, and the volume is given as 112.4 mL. First, we need to convert the mass to grams, since the density is usually measured in g/mL. There are 28.35 grams in an ounce, so the mass of the unknown substance is 8.3 oz x 28.35 g/oz = 235.005 g. Now we can calculate the density by dividing the mass by the volume: density = 235.005 g / 112.4 mL = 2.091 g/mL.

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