Final answer:
The equations x = 4 - y and y² = 3x can be solved by substituting x from the first equation into the second, resulting in a quadratic equation that can be factored. The solutions are x = 8, y = -4 and x = 1, y = 3.
Step-by-step explanation:
Let's solve the given simultaneous equations:
x = 4 - y (Equation a)
y² = 3x (Equation b)
We can substitute the expression for x from equation a into equation b:
y² = 3(4 - y)
Expanding and rearranging the equation:
y² = 12 - 3y
Moving all terms to one side:
y² + 3y - 12 = 0
This is a quadratic equation, which can be factored to:
(y + 4)(y - 3) = 0
So the solutions for y are:
Substituting these values back into equation a:
- For y = -4:
- x = 4 - (-4) = 8
- For y = 3:
- x = 4 - 3 = 1
Therefore, we have two sets of solutions for the simultaneous equations:
- Solution 1: x = 8, y = -4
- Solution 2: x = 1, y = 3