Question

A 17.6-g sample of ammonium carbonate contains ________ mol of ammonium ions.

A. 1.0 mol
B. 2.0 mol
C. 3.0 mol
D. 4.0 mol

Answer 1

The 17.6 g sample of ammonium carbonate contains 0.366 moles of ammonium ions.

Step-by-step explanation:

The molar mass of ammonium carbonate (NH4)2CO3 is 96.085 g/mol. To calculate the number of moles of ammonium ions in a 17.6 g sample, divide the mass of the sample by the molar mass:

Number of moles = Mass of sample / Molar mass

Number of moles = 17.6 g / 96.085 g/mol = 0.183 mol

Since one formula unit of ammonium carbonate contains two ammonium ions (NH4+), the 17.6 g sample contains 2 * 0.183 mol = 0.366 mol of ammonium ions.

Therefore, the answer is 0.366 moles of ammonium ions.