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Solve the equation in the interval [0,2π] cos(x)= sqrt3/2

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Final answer:

The equation cos(x) = √3/2 is solved within the interval [0,2π], yielding the angles x = π/6 and x = 11π/6 as the solutions.

Step-by-step explanation:

To solve the equation cos(x) = √3/2 in the interval [0,2π], we first need to identify the angles where the cosine value is √3/2. The cosine function has this value at angles of π/6 (30°) and 11π/6 (330°) within one full circle (0 to 2π). Since cosine is positive in the first and fourth quadrants, these are the only solutions in the given interval.

Here's a step-by-step process to find these solutions:

  1. Looking at the unit circle, we identify where the cosine value is √3/2.
  2. We find that this occurs at angles π/6 and 11π/6.
  3. Check that both solutions are within the given interval [0,2π].

Therefore, the solutions to the equation cos(x) = √3/2 in the interval [0,2π] are x = π/6 and x = 11π/6.

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